Work

W = Fd\cos\theta = 100\ J

Work done100.0 J

Power25.0 W

Effective force (F cos θ)20.0 N

Force (N)20

Displacement (m)5

Angle to motion (°)0

Time taken (s)4

With the force acting straight along the motion (0°), confirm work = force × displacement
Set the angle to 90° and confirm the work done is exactly zero
With force = 20 N and displacement = 5 m at 0°, confirm the work done reads exactly 100 J
Set the angle beyond 90° and confirm the work done becomes negative
With 100 J of work done over 4 seconds, confirm the power reads exactly 25 W